40. 50ml H2O is added to a 50ml solution of Ba(OH)2 of strenth 0.01M. The pH value of the resuultingsolution will be
![OneClass: 3. Consider the reaction: 2HCl(aq) + Ba(OH)2(a) â†' BaCl2(aq) + 2 H2O(l) Δ --118 kl A) Cal... OneClass: 3. Consider the reaction: 2HCl(aq) + Ba(OH)2(a) â†' BaCl2(aq) + 2 H2O(l) Δ --118 kl A) Cal...](https://prealliance-textbook-qa.oneclass.com/qa_images/homework_help/question/qa_images/120/12091590.png)
OneClass: 3. Consider the reaction: 2HCl(aq) + Ba(OH)2(a) â†' BaCl2(aq) + 2 H2O(l) Δ --118 kl A) Cal...
![Ba + H2O =Ba(OH)2 +H2 Balanced Equation||Barium and Water=Barium hydroxide plus H2 Balanced Equation - YouTube Ba + H2O =Ba(OH)2 +H2 Balanced Equation||Barium and Water=Barium hydroxide plus H2 Balanced Equation - YouTube](https://i.ytimg.com/vi/hATu8WopIKI/hqdefault.jpg)
Ba + H2O =Ba(OH)2 +H2 Balanced Equation||Barium and Water=Barium hydroxide plus H2 Balanced Equation - YouTube
![рассчитайте по термохимическому уравнению BaO+H2O=Ba(OH)2+73 кДж сколько выделяется энергии - Школьные Знания.com рассчитайте по термохимическому уравнению BaO+H2O=Ba(OH)2+73 кДж сколько выделяется энергии - Школьные Знания.com](https://ru-static.z-dn.net/files/d69/4ee6969e9744a98c40d5bf8e7228b0e5.png)
рассчитайте по термохимическому уравнению BaO+H2O=Ba(OH)2+73 кДж сколько выделяется энергии - Школьные Знания.com
BALANCE THIS GIVEN EQUATION BY THE HELP OF THE ALTERNATE WAY OF BALANCING NOT THE TRADITIONAL WAY BY SHOWING THE APPROPRIATE STEPS ELABORATELY. EQN : Ba(OH)2 + NH4Cl —> BaCl2 + NH3 + H2O
![SOLVED: Consider the unbalanced equation for the neutralization of acetic acid: HC2H3O2(aq) + Ba(OH)2(aq)-H2O(l ) + Ba(C2H3O2)2(aq) Balance the equation and determine how many moles of Ba(OH)2 are required to completely neutralize SOLVED: Consider the unbalanced equation for the neutralization of acetic acid: HC2H3O2(aq) + Ba(OH)2(aq)-H2O(l ) + Ba(C2H3O2)2(aq) Balance the equation and determine how many moles of Ba(OH)2 are required to completely neutralize](https://cdn.numerade.com/ask_previews/e0f5413f-0ab9-4f67-b7e4-da02e6971382_large.jpg)